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x^2-234=5x
We move all terms to the left:
x^2-234-(5x)=0
a = 1; b = -5; c = -234;
Δ = b2-4ac
Δ = -52-4·1·(-234)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-31}{2*1}=\frac{-26}{2} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+31}{2*1}=\frac{36}{2} =18 $
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